Given a binary tree, flatten it to a linked list in-place.
For example, given the following tree:
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
Return the leaf node of a flattened subtree for concatenation.
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {void} Do not return anything, modify root in-place instead.
*/
var flatten = function(root) {
_flatten(root)
};
/**
* @param {TreeNode} root
* @return {TreeNode} leaf node of a flattened subtree
*/
function _flatten (root) {
if (!root) { return null }
const leftLeaf = _flatten(root.left)
const rightLeaf = _flatten(root.right)
if (leftLeaf !== null) {
leftLeaf.right = root.right
root.right = root.left
} else if (rightLeaf === null) {
return root
}
root.left = null
return rightLeaf || leftLeaf
}