Reverse a linked list from position m to n. Do it in one-pass.
Note:1 ≤ m ≤ n ≤ length of list.
Example:
Input: 1->2->3->4->5->NULL, m = 2, n = 4
Output: 1->4->3->2->5->NULL
Break the list into 3 parts.
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} head
* @param {number} m
* @param {number} n
* @return {ListNode}
*/
var reverseBetween = function(head, m, n) {
if (m === n) { return head }
const prehead = { next: head }
n = n - m
let l1tail = prehead
while (--m > 0) {
l1tail = l1tail.next
}
let l2prehead = l1tail
let l2head = l2prehead.next
let l2tail = l2head
while (n-- > 0) {
const next = l2head.next
l2head.next = l2prehead
l2prehead = l2head
l2head = next
}
l2tail.next = l2head.next // l3head
l2head.next = l2prehead
l1tail.next = l2head
return prehead.next
};
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