Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
Example:
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Loop backward and keep picking the larger one. nums1
is
guaranteed longer than nums2
so just use n
as
boundary.
/**
* @param {number[]} nums1
* @param {number} m
* @param {number[]} nums2
* @param {number} n
* @return {void} Do not return anything, modify nums1 in-place instead.
*/
var merge = function(nums1, m, nums2, n) {
let len = (m--) + (n--)
while (n >= 0) {
nums1[--len] = nums1[m] >= nums2[n] ? nums1[m--] : nums2[n--]
}
};
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