You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix =
[
[1,2,3],
[4,5,6],
[7,8,9]
],
rotate the input matrix in-place such that it becomes:
[
[7,4,1],
[8,5,2],
[9,6,3]
]
Example 2:
Given input matrix =
[
[ 5, 1, 9,11],
[ 2, 4, 8,10],
[13, 3, 6, 7],
[15,14,12,16]
],
rotate the input matrix in-place such that it becomes:
[
[15,13, 2, 5],
[14, 3, 4, 1],
[12, 6, 8, 9],
[16, 7,10,11]
]
Outside-in. Rotate one square at a time.
/**
* @param {number[][]} matrix
* @return {void} Do not return anything, modify matrix in-place instead.
*/
var rotate = function(matrix) {
if (!matrix || matrix.length <= 0) {
return
}
const width = matrix.length
const halfWidthFloor = Math.floor(width / 2)
const halfWidthCeil = Math.ceil(width / 2)
for (let i = 0; i < halfWidthFloor; i++) {
const iend = width - 1 - i
for (let j = 0; j < halfWidthCeil; j++) {
const jend = width - 1 - j
const tmp = matrix[i][j]
matrix[i][j] = matrix[jend][i];
matrix[jend][i] = matrix[iend][jend]
matrix[iend][jend] = matrix[j][iend]
matrix[j][iend] = tmp
}
}
};
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