Given an array nums of n integers and an integer
target, find three integers in nums such that
the sum is closest to target. Return the sum of the three
integers. You may assume that each input would have exactly one solution.
Example:
Given array nums = [-1, 2, 1, -4], and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
Simplified version of 15. 3Sum.
/**
* @param {number[]} nums
* @param {number} target
* @return {number}
*/
var threeSumClosest = function(nums, target) {
const len = nums.length
const sorted = nums.sort((a, b) => a - b)
let minDiff = Infinity
for (let i = 0; i < len - 2; i++) {
if (i > 0 && sorted[i] === sorted[i-1]) {
continue
}
const twoSum = target - sorted[i]
for (let l = i + 1, r = len - 1; l < r;) {
const diff = twoSum - sorted[l] - sorted[r]
if (diff === 0) {
return target
} else {
if (diff > 0) {
l++
} else {
r--
}
if (Math.abs(diff) < Math.abs(minDiff)) {
minDiff = diff
}
}
}
}
return target - minDiff
};