Given an array nums
of n integers and an integer
target
, find three integers in nums
such that
the sum is closest to target
. Return the sum of the three
integers. You may assume that each input would have exactly one solution.
Example:
Given array nums = [-1, 2, 1, -4], and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
Simplified version of 15. 3Sum.
/**
* @param {number[]} nums
* @param {number} target
* @return {number}
*/
let threeSumClosest = function(nums, target) {
const len = nums.length
const sorted = nums.sort((a, b) => a - b)
let minDiff = Infinity
for (let i = 0; i < len - 2; i++) {
if (i > 0 && sorted[i] === sorted[i-1]) {
continue
}
const twoSum = target - sorted[i]
for (let l = i + 1, r = len - 1; l < r;) {
const diff = twoSum - sorted[l] - sorted[r]
if (diff === 0) {
return target
} else {
if (diff > 0) {
l++
} else {
r--
}
if (Math.abs(diff) < Math.abs(minDiff)) {
minDiff = diff
}
}
}
}
return target - minDiff
};