Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward.
Example 1:
Input: 121
Output: true
Example 2:
Input: -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Follow up:
Coud you solve it without converting the integer to a string?
Easy to write but slow since it generates an array.
/**
* @param {number} x
* @return {boolean}
*/
let isPalindrome = function(x) {
return x == String(x).split('').reverse().join('')
};
A bit faster.
/**
* @param {number} x
* @return {boolean}
*/
let isPalindrome = function(x) {
const s = String(x)
for (let i = 0, j = s.length -1; i < j; i++, j--) {
if (s[i] !== s[j]) {
return false
}
}
return true
};
General solution. Combining 7. Reverse Integer.
/**
* @param {number} x
* @return {boolean}
*/
let isPalindrome = function(x) {
if (x < 0) { return false }
return x === reverse(x)
};
/**
* @param {number} x
* @return {number}
*/
function reverse (x) {
let result = 0
while (x) {
result = result * 10 + x % 10
x = x / 10 | 0
}
return result
};