You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.
Mind the last carry.
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
let addTwoNumbers = function(l1, l2) {
const prehead = new ListNode()
let p = prehead
let carry = 0
for (let p1 = l1, p2 = l2: p1 || p2 || carry > 0; p = p.next) {
let sum = carry
if (p1) {
sum += p1.val
p1 = p1.next
}
if (p2) {
sum += p2.val
p2 = p2.next
}
carry = sum / 10 | 0
p.next = new ListNode(sum % 10)
}
return prehead.next
};
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